If you compare table values to answer choices, you can see right away that several don't work. The number of centimeters is greater than the number of inches, so adding to or multiplying the number of centimeters by some number more than 1 will not give you the smalller number that is inches.
While it may work for the first number (5 inches) to add 7.7 to get the first number of centimeters (12.7), you have to know that you can only add like to like. You can only add inches to inches (getting a result of inches), or centimeters to centimeters (getting a result of centimeters). From the point of view of the units involved, it is <em>nonsensical</em> to add a pure number to a number of inches and expect to get a number of centimeters.
So, we're down to the second choice:
- The number of inches is multiplied by 2.54 to find the number of centimeters.
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To find the pattern in the table, you can ...
- observe that the inch values differ by 1
- observe that the centimeter values differ by 2.54
- realize that the constant differences mean the relation between inches and centimeters is linear, and that a change in an inch value of 1 inch is multiplied by 2.54 to find the corresponding change in centimeter value.
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I don't know what the first step in your problem solving process is supposed to be. In my problem solving process, the first step is always to <em>look at what you are given</em>. The next step is <em>look at what you are being asked for</em>.
9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
C. Wich mean she worked 5 hours and half an hour (0.5)
A suitable statistics calculator gives the probability that 6 or more show up as being about ...
0.2539
