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2 years ago

Factorise completely: 1. 3xy - x2. 4a² - 9

Mathematics

1 answer:

Amanda [17]2 years ago

6 0

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

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Given the triangle below, which of the following is a correct statement?

EleoNora [17]

ANSWER

(A)csc angle C equals 3 over 2

EXPLANATION

The cosecant is hypotenuse over opposite.

$\csc(C) = \frac{6}{4}$

$\csc(C) = \frac{3}{2}$

$\csc(B) = \frac{6}{5}$

The secant is the hypotenuse over adjacent.

$\sec(C)=\frac{6}{5}$

$\sec(B) = \frac{6}{4}$

$\sec(B) = \frac{3}{2}$

The only correct choice is A

5 0

3 years ago

Read 2 more answers

Howis 1/8 greater than 3/16?

Basile [38]

You have $\dfrac18=\dfrac2{16}$ , so that's not true.

8 0

2 years ago

Question 2 Multiple Choice Worth 1 points)

Sati [7]

Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

<h3>Transformation of function</h3>

Transformation is a techniques use to change the position of an object on an xy-plane.

Given the parent function f(x) = x² and the function g(x) = x²-12x +36

Factorize g(x);

g(x) = x²-6x-6x+36

g(x)=x(x-6)-6(x-6)

Group the terms to have;

g(x) = (x-6)²

Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

Learn more on transformation here: brainly.com/question/4289712
#SPJ1

4 0

1 year ago

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne

Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

$H_0: \bar x =12.7\\H_a: \bar x >12,7$