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Anna11 [10]
3 years ago
10

I need help with this assignment help

Mathematics
1 answer:
saw5 [17]3 years ago
4 0

Table:

4 cups of water, 5 cups of flour.

9 cups of water, 10 cups of flour.

16 cups of water, 17 cups of flour.

29 cups of water, 30 cups of flour.

Equation:

f-1=w

Independent variable:

F

Dependent variable:

W

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Slope of (10,8) (2,1)
Reptile [31]

Answer:

slope=7/8

Step-by-step explanation:

8-1/10-2= 7/8

6 0
3 years ago
A gift box is the shape of a rectangular prism. The box has a length of 24 centimeters, a width of 10 centimeters, and a height
Kamila [148]
Volume (V) is (=) Length (L) times (x) Width (W) times (x) Height (H) so V = L x V x H. 

Add the variables to the equation.
V = 24 x 10 x 13

Solve
V = 3120

So the volume of the gift box is 3120 cm
6 0
3 years ago
You can represent the measures of an angle and its complement as x °and (90 - x). Similarly, you can
Tanzania [10]

Answer:

  1. 33°
  2. 90° -J°

Step-by-step explanation:

<h3>1)</h3>

If x represents the measure of the angle, its complement is 90-x. The problem statement tells us ...

  x +24 = 90 -x

  2x = 66 . . . . . add x-24

  x = 33 . . . . . . divide by 2

The measure of the angle is 33°.

__

<h3>2)</h3>

Using J for x in the given complement relation:

The measure of the complement of J° is (90 -J)°.

5 0
3 years ago
In an experiment using 30 mice, the sample proportion of the mice that gained weight after a drug injection is 0.65. What is the
lisabon 2012 [21]
D: between 0.389 and 0.911
3 0
3 years ago
Read 2 more answers
Of interest is to determine the mean age of students at the time they take the comprehensive exam for all students enrolled in g
Gnoma [55]

Answer:

The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 31 - 1 = 30

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.457

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.457\frac{2.9}{\sqrt{31}} = 1.3

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 27.5 - 1.3 = 26.2 years

The upper end of the interval is the sample mean added to M. So it is 27.5 + 1.3 = 28.8 years

The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.

8 0
3 years ago
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