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abruzzese [7]
3 years ago
7

The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49

Mathematics
1 answer:
KIM [24]3 years ago
3 0

<u>Answer:</u>

<u>For 1:</u> The first term is 10 and the common difference is \frac{3}{2}

<u>For 2:</u> The value of n is 27

<u>Step-by-step explanation:</u>

The n-th term of the progression is given as:

a_n=a_1+(n-1)d

where,

a_1 is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

S_n=\frac{n}{2}[2a_1+(n-1)d]

where,

S_n is the sum of nth terms

  • <u>For (1):</u>

The 11th term of the progression:

25=a_1+10d               .......(1)

Sum of first 4 numbers:

49=\frac{4}{2}[2a_1+3d              ......(2)

Forming equations:

98=8a_1+12d

25=a_1+10d                  ( × 8)

The equations become:

98=8a_1+12d

200=8a_1+80d

Solving above equations, we get:

102=68d\\\\d=\frac{102}{68}=\frac{3}{2}

Putting value in equation (1):

25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10

Hence, the first term is 10 and the common difference is \frac{3}{2}

  • <u>For 2:</u>

The nth term is given as:

49=10+(n-1)\frac{3}{2}

Solving the above equation:

39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27

Hence, the value of n is 27

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Complete question :

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