Answer:
6 2/3.. i think
Step-by-step explanation:
hopefully u understand my messy handwriting
The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
<h3>What is the range of the function?</h3>
Range of a function is the set of all the possible output values which are valid for that function.
The trigonometry function given in the problem is,

The above function can be written as,

The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.

This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,

Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
Learn more about the range of the function here;
brainly.com/question/2264373
Answer:
A
Step-by-step explanation:

Total amount of money received by David for working at his father's store = $50
Amount of money spent by David at the movies = $20
Amount of money spent by David buying comics books = $10
Amount of money spent by David buying candy = $5
Then
Total amount spent by David = (20 + 10 + 5) dollars
= 35 dollars
Amount of money saved by David = (50 - 35 ) dollars
= 15 dollars
So
The ratio of the amount of money David
spent to the amount of money David saved = 35:15
= 7:3
So the ratio of the amount of money David spent to the amount of money David saved is 7:3
<em>Answer:</em>
<em>r = -</em>
<em />
<em>Step-by-step explanation:</em>
<em>Rewrite the equation as </em>
<em> = m</em>
<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>
<em>(</em>
<em> = m^2</em>
<em>Then, you simplify each of the equation. </em>
<em>Rewrite: (</em>
<em> as </em>
<em />
<em>Remove any parentheses if needed.</em>
<em>Solve for r. </em>
<em>Multiply each term by r and simplify."</em>
<em>Multiply both sides of the equation by 5.</em>
<em>6a+r= m^2r⋅(5)</em>
<em>Remove parentheses.</em>
<em>Move 5 to the left of (m
^2) r
</em>
<em>6a+r=5m^2)r</em>
<em>Subtract 5m^2)r from both sides of the equation.</em>
<em>6a+r-5m^2)r=0</em>
<em>Subtract 6a from both sides of the equation.</em>
<em>r-5m^2)r=-6a</em>
<em>Factor r out of r-5m^2)r </em>
<em>r(1-5m^2)=-6a</em>
Divide each term by 1-5m^2 and simplify.
r = - 
There you go, hope this helps!