Pls help me I just need the math equation y=mx thing thx!

The first five multiples for the numbers 4 and 6

exis [7]

Answer:

4: 4,8,12,16,20

6: 6,12,18,24,30

Step-by-step explanation:

7 0

3 years ago

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Valor de expresión numérica 4÷3-8+7÷2-10+2÷6

Iteru [2.4K]

Answer:

-12.833 OR -77/6

Step-by-step explanation:

B rackets

P arentheses

E xponent

M ultipication

D ivision

A ddition

S ubtraction

8 0

3 years ago

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In triangle ABC angle c is a right angle find the value of the trig function indicated. find sec A if c=25, a=7

siniylev [52]

Check the picture below.

3 0

4 years ago

A sign on the gas pumps of a chain of gasoline stations encourages customers to have their oil checked with the claim that one o

ELEN [110]

Answer:

a) 0.4219 = 42.19% probability that one out of the next four cars needs oil.

b) 0.3115 = 31.15% probability that two out of the next eight cars needs oil.

c) 0.2581 = 25.81% probability that three out of the next 12 cars need oil.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they need oil, or they do not need it. The probability of a car needing oil is independent of any other car, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

One out of four cars needs to have oil added.

This means that $p = \frac{1}{4} = 0.25$

a. One out of the next four cars needs oil.

This is P(X = 1) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{4,1}.(0.25)^{1}.(0.75)^{3} = 0.4219$

0.4219 = 42.19% probability that one out of the next four cars needs oil.

b. Two out of the next eight cars needs oil.

This is P(X = 2) when n = 8. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{8,2}.(0.25)^{2}.(0.75)^{6} = 0.3115$

0.3115 = 31.15% probability that two out of the next eight cars needs oil.

c.Three out of the next 12 cars need oil.

This is P(X = 3) when n = 12. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.25)^{3}.(0.75)^{9} = 0.2581$

0.2581 = 25.81% probability that three out of the next 12 cars need oil.

6 0

3 years ago

The cost of riding in a cab is $3.00 plus $0.75 per mile. The equation that represents this relation is y = 0.75x +3, where x is

Gemiola [76]

Answer:

Yes, the relation is a function.

Step-by-step explanation:

Given:

The equation that represents the cost of riding a cab is given as:

$y=0.75x+3$

Where, 'x' is the number of miles traveled and 'y' is the the total cost of the trip.

The above equation represents a line as it is of the form $y=mx+b$ which represents a line with constant slope.

Now, in order to plot this equation, we need at least two points.

Now, let $x =0$ , then

$y=0.75(0)+3=3$ . So, (0, 3) is a point on the line.

Let $x =1$ , then

$y=0.75(1)+3=3.75$ . So, (1, 3.75) is a point on the line.

Plot these two points on a graph and draw a line passing through these two points.

Now, for a relation to be a function, it should pass the vertical line test.

According to vertical line test, vertical lines passing through the graph must cut the graph at only 1 point for the graph to represent a function.

Here, we observe that vertical lines passing through the line will intersect the line only at one point. So, it represent a function.

8 0

4 years ago