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3 years ago

Evaluate functions help !easy please help fast!

Mathematics

1 answer:

yarga [219]3 years ago

6 0

Answer:

Step-by-step explanation:

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Rewrite `10^{32}\ \/ \ 10^{6}\ `using a single exponent.

IrinaVladis [17]

Answer:

10^38

Step-by-step explanation: :)

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3 years ago

Use the distributive property to complete the following statement 4(x-1)=4x-___

Flura [38]

Answer:

A. 4

Step-by-step explanation:

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2 years ago

What is 31 billion in scientific notation? <br><br> explain clearly <3 :D

MArishka [77]

Answer:

3.1*10^10

Step-by-step explanation:

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2 years ago

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Kitty [74]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0

2 years ago