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gizmo_the_mogwai [7]
3 years ago
5

Evaluate functions help !easy please help fast!

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

70

Step-by-step explanation:

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Fill in the numbers to find a Sum
Alekssandra [29.7K]

Answer:

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

Step-by-step explanation:

we have

\frac{2}{10} +\frac{x}{100} =\frac{5}{y}

Solve the left side

\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}

so

\frac{20+x}{100}=\frac{5}{y}

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

4 0
3 years ago
What is the answer to this problem<br> -69=7v-6
alex41 [277]

-69= 7v-6 so v equals 74 or something


5 0
3 years ago
Please answer the question soon! (Select all that apply)
lisov135 [29]

Answer:

Step-by-step explanation:

ES LA A

5 0
3 years ago
Percy said that any real number for k would cause the system of equations to have no solution. Explain the error in Percy’s stat
MatroZZZ [7]

Answer:

Except k=7, any real number for k would cause the system of equations to have no solution.

Step-by-step explanation:

In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.

Just for information, if k=7 the system will have infinitely many solutions.

5 0
3 years ago
Read 2 more answers
11)
Alinara [238K]

Answer:

92

Step-by-step explanation:

3 0
3 years ago
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