D is a line, K is a point, beta is a plane and PY is a line segment.
Solution :
2a + 2b = 7 ...1)
4a + 3b = 12 ...2)
In equation, 1)
a = (7 - 2b)/2 ...3)
Putting value of a in equation 2) we get :
4 × (7 - 2b)/2 + 3b = 12
2( 7 - 2b ) + 3b = 12
14 - 4b + 3b = 12
b = 2
Putting value of b in 3) we get :
a = ( 7 - 2×2)/2
a = 3/2 = 1.5
Now,
2x - 3y = 16 ...5)
x + 2y = -6 ...6)
x = -6 - 2y
Putting above value of x in eq 5) , we get :
2( -6 - 2y ) - 3y = 16
-12 - 4y - 3y = 16
7y = -28
y = -4
x = -6 - ( 2× -4 )
x = 2
Hence, this is the required solution.
Answer:
No the triangle are not same because the outer length of triangle is not same
Answer:
(b)
P = [4(4a + 3b]/(2a + b)
Step-by-step explanation:
P = 2L + 2W
P = [2(5a + 4b) + 2(3a + 2b)]/(2a + b)
P = [10a + 8b + 6a + 4b]/(2a + b)
P = [16a + 12b]/(2a + b)
P = [4(4a + 3b]/(2a + b)