Actually, i think something is missing here:
You need either a parenthesis or some dots at the end to determine this. A repeating decimal can have one repreating digit:
0.(7): 0.777777...
two:
0.(45): 0.45454545454545....
or more: so potentially all of them can be repeating, even a!
it could be: 1.(111114)
or: 1.111114111114111114111114111114111114111114111114111114111114111114111114111114...
proably B. is the most typical of repeating decimals (choosed this one if you have to), but in reality, you need more information... did you copy the question exactly?
You multiply both of the equations until you have two of the same term the same like for example, say I have 4x and 5x. You want to multiply until both have the same number, so multiply 5x by four, then multiply 4x by five, and you will get 20x, then both of those cancel out and you will be left with the other variable, and you just solve like a normal equation.
Pemdas
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64
