let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.
![\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20sin%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B5%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B6%7D%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Badjacent%20side%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Cpm%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cpm%5Csqrt%7B6%5E2-5%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B36-25%7D%5Cimplies%20%5Cpm%20%5Csqrt%7B11%7D%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
Step-by-step explanation:
The slope of all lines in quadrant 1 is positive. FALSE
The slope of a line does not depend on the quadrant.
The slope of <u>all lines</u> that pass through the origin is undefined.FALSE
The slope of some lines that pass trough the origin are undefined ( lines that are vertical have undefined slope)
The larger the slope, the longer the line.FALSE
The lines do not get longer or shorter because they go to infinity in both directions.
The larger the magnitude of the slope value, the steeper the line. TRUE
The larger the absolute value of the slope the steeper the slope.
Answer:
AG = 4
AH = 21
EC = 12
CH = 5
HE = 7
Step-by-step explanation:
<u><em>The complete question is</em></u>
The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.
Which of the following statements are true? Select all that apply.
•AG = 4
•GC = 10
•AH = 21
•EC = 12
•EH = 5
•CH = 5
•HE = 7
The picture of the question in the attached figure
<u><em>Verify each statement</em></u>
1) AG = 4
we know that

----> radius of circle A
----> radius of circle C
substitute

therefore
The statement is true
2) GC = 10
we know that
----> radius of circle C
therefore
The statement is false
3) AH = 21
we know that

we have
----> radius of circle A

----> radius of circle C
----> radius of circle E
so


therefore
The statement is true
4) EC = 12
we know that
----> radius of circle C
therefore
The statement is true
5) EH = 5
we know that
----> radius of circle E
therefore
The statement is false
6) CH = 5
we know that

----> radius of circle C
----> radius of circle E
so

therefore
The statement is true
7) HE = 7
we know that
----> radius of circle E
therefore
The statement is true
Some of the important "given" information is outside of the photo.
We need to know that the two triangles are similar.
And we need to know that the WHAT ? of angle M is 9/40.