Use ratio language to describe the relationship between 2 dogs and 1 cat

-12=-2(2-8) Is it true false or an open sentence

MissTica

The statement is false because when you use distributive property, you get -12=-4+16 and when you add 16 to -4, you'll get 12, not -12, making the statement false.

7 0

3 years ago

Read 2 more answers

Marco wants to buy a game for $59.99. The sales tax is 7%. How much will he pay for the sales tax?

Kamila [148]

Answer:

$4.19

Step-by-step explanation:

8 0

3 years ago

What is the equation of the line written in general form

Vesnalui [34]

Answer:

y = -x + 2.

or

x + y - 2 = 0 (Standard form).

Step-by-step explanation:

Its slope (m) is -1 and y intercept (c) is at y = 2.

y = mx + c

So it's:

y = -1x + 2

Standard form is:

x + y - 2 = 0.

I'm not sure what you mean by General Form.

5 0

2 years ago

A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco

sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

Let p = proportion of all cars in San Francisco who are blue

SO, Null Hypothesis, $H_0$ : p = 25% {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 600 cars in San Francisco who are blue = $\frac{141}{600}$ = 0.235

n = sample of cars = 600

So, test statistics = $\frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }$

= -0.866

Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0

3 years ago

Jimmy had some raisins. he ate 6 of them.

Law Incorporation [45]

If Jimmy ate 6 of them, 6 of them are gone.

g= the number of raisins he started out with

g-6 <--- the answer

"B" is the answer.

I hope this helps!
~kaikers

6 0

3 years ago