Answer:
Step-by-step explanation:
6x^2+4x-42
2(3x^2+2x-21)=0
3x^2+2x-21=0
3x^2+(9-7)x-21=0
3x^2+9x-7x-21=0
3x(X+3)-7(X+3)=0
(3X-7)(X+3)=0
So Answer is (3x-7)(X+3)
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
It would be 10 because 7000 can go into 70,000 10 times. You can you a calculator or look at the zeros take away the 3 zeros in 7000 and then 3 zeros in 70,000 making it 7 and 70 and 7 goes into 70 10 times as well. I hope this helps!
By definition, we have to:
In plane geometry, a rectangle is a parallelogram whose four sides are at right angles to each other. Opposite sides have the same length.
There is a proof that a quadrilateral is a rectangle:
1) Its parallel sides are the same.
2) Its two diagonals are the same, and they bisect each other at the common midpoint
3) Any rectangle can be inscribed in a circle, two of whose diameters coincide with the diagonals of the rectangle.
4) If all the angles of a quadrilateral are right angles, then it is a rectangle
Answer:
20
Step-by-step explanation:
