1/4a + 1/3a +8 =22
1st step add like terms:
1/4a +1/3a = 3/12a +4/12a = 7/12a
7/12a +8 =22
2nd step subtract 8 from each side:
7/12a = 14
3rd step divide both sides by 7/12 to get a:
a = 14 / 7/12
a = 24
Answer:
Cost = 616000 DHS per square centimetre.
Step-by-step explanation:
curved surface of a cylinder = 2
rh
r = 7 cm
h = 1400 m = 140000 cm
The outer curved surface area of the cylinder = inner curved surface area of the cylinder
The inner curved surface of the cylinder = 2
rh
= 2 x
x 7 x 140000
= 2 x 22 x 1 x 140000
= 6160000
The inner curved surface of the cylinder is 6160000 square centimetre.
But, the cost of painting is at the rate of 10 DHS per square centimetre.
The inner curved surface of the cylinder = 6.16 x
square centimetre.
cost of painting the inner curved surface area = 
= 616000 DHS per square centimetre
The cost of painting the inner surface is 616000 DHS per square centimetre.
Answer to question is y=-5x-11
Step-by-step explanation:
1/2 + 3/4
= 2/4 + 3/4
= 5/4
= 1 and 1/4 miles
Answer:
A) 48 in : initial height of the water
B) 40.5 in : height of the water after 5 days
C) 32 days
D) Yes, should be restricted.
Domain: 0 ≤ d ≤ 32
Step-by-step explanation:

A)

48 in is the initial height of the water
B)

40.5 in is the height of the water after 5 days
C) when the pool is empty, h = 0.
So set the equation to zero and solve for d.

D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative
Domain: 0 ≤ d ≤ 32