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Kobotan [32]
2 years ago
5

Point B is on line segment AC. Given AB 3x, BC = 4x + 8, and

Mathematics
1 answer:
8090 [49]2 years ago
5 0
I have no clue i’m sry i just need points 627 x a
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This one is the one I need help with my final question
STatiana [176]

Answer:

vertex C could be at (6,0) or (2,8)

(I'm sorry if I'm wrong, but if not I hope this helps!)

Step-by-step explanation:

vertex C needs to be placed somewhere on the graph where it would form a right angle (and therefore a right-angled triangle as well). vertex C could be at (6,0) or (2,8). this is because at these two points vertex C will form a right angle, therefore making it a right-angled triangle.

7 0
3 years ago
Solve for X<br> 6(x + 2) = 66<br> X =
ioda

Answer:

6(x+2)=66

6x+12=66 -12

6x= 54 :6

x=9

Step-by-step explanation:

prove me wrong

4 0
3 years ago
Four times the sum of a number and 15 is at least 120. Find all possible solutions for x
zloy xaker [14]
First translate the English phrase "Four times the sum of a number and 15 is at least 120" into a mathematical inequality.

"Four times..." means we're multiplying something by 4.

"... the sum of a number and 15..." means we're adding an unknown and 15 and then multiplying the result by 4.

"... is at least 120" means when we substitute the unknown for a value, in order for that value to be in the solution set, it can only be less than or equal to 120.

So, the resulting inequality is 4(x + 15) ≤ 120.

Simplify the inequality.

4(x + 15) ≤ 120
4x + 60 ≤ 120 <-- Using the distributive property
4x ≤ 60 <-- Subtract both sides by 60
x ≤ 15 <-- Divide both sides by 4

Now that we have the inequality in a simplified form, we can easily see that in order to be in the solution set, the variable x can be no bigger than 15.

In interval notation it would look something like this:

[15, ∞)

In set builder notation it would look something like this:

{x | x ∈ R, x ≤ 15}

It is read as "the set of all x, such that x is a member of the real numbers and x is less than or equal to 15".
7 0
3 years ago
Circle O shown below has a radius of 21 inches. Find, to the nearest tenth, the radian
lord [1]

Answer:

He's right it's 0.8 I got the answer right thanks a lot dude

8 0
3 years ago
I have a few questions:
inn [45]
Hello,
Please, see the attached files.
Thanks.

3 0
2 years ago
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