Answer:
(x + 1) (3 x^2 + 1)
Step-by-step explanation:
Factor the following:
3 x^3 + 3 x^2 + x + 1
Factor terms by grouping. 3 x^3 + 3 x^2 + x + 1 = (3 x^3 + 3 x^2) + (x + 1) = 3 x^2 (x + 1) + (x + 1):
3 x^2 (x + 1) + (x + 1)
Factor x + 1 from 3 x^2 (x + 1) + (x + 1):
Answer: (x + 1) (3 x^2 + 1)
Answer:
Step-by-step explanation:
I am going to explain this using the substitution method, considering it appears to be the best in this situation.
We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:
3x+20=x^2+2x
Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you
x+20=x^2
Now, we take the square root of both sides to get
rad(x+20)=x
Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes
2rad(x+5)
This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
Answer:
Option B is correct.
Step-by-step explanation:
We have given a triangle ABC and EDC please look at the figure
We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles
And ∠ACB=∠DCE are vertically opposite angles hence, equal
So, by AA similarity postulate the above to triangles are similar
ΔABC 
ΔEDC
Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5
NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE
And m∠1 = m∠5 corresponds to m∠EAB=m∠AED
Answer:
x ∈ {-3, 1.2, 1.25}
Step-by-step explanation:
"Solve" is non-specific as to the solution required. We assume you want the x-intercepts.
A graph shows the zeros to be ...
The equation can be factored as ...
y = (1/2)(x +3)(4x -5)(5x -6)
