Let, coordinate of point A' is (x,y).
Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.
So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.
Now, their center is given by :
Also, product of slope will be -1 .( Since, they are parallel )
x = 2y - 1
So, 
Also, C satisfy given line :
Also,
Therefore, the symmetric points is
.
Its simple, graph them.
For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.
For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.
When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.
I hope this cleared up your confusion, brainliest/heart would help.
Answer:
28
Step-by-step explanation:
First, you start with 11-4, which equals 7.
Then, you multiply 7x8 which equals 56.
Lastly, you divided 56 by 2, getting 28.
Answer:
Step-by-step explanation:
Student 2 and student 1
The corresponding parts that are congruent are (a) AB and DE
<h3>How to determine the congruent parts?</h3>
The statement ΔABC ≅ ΔDEF means that the triangles ABC and DEF are congruent.
This implies that the following points are corresponding points:
A and D; B and E; C and F
When two corresponding points are joined together, the congruent parts are:
AB and DE, AC and DF, BC and EF
Hence, the corresponding parts that are congruent are (a) AB and DE
Read more about congruent triangles at:
brainly.com/question/1675117
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