3 years ago

In RST, R = 23* and S = 136*. Which list has the sides of RST in order from shortest to longest?

Mathematics

2 answers:

Alik [6]3 years ago

7 0

Answer:

RS, ST, TR

Step-by-step explanation:

The third angle measures:

T = 180° - (136° + 23°) = 21°

Angles and opposite sides are:

S = 136° → TR
R = 23° → ST
T = 21° → RS

The greater the angle, the greater the opposite side, therefore the sides in increasing order will be:

RS, ST, TR

exis [7]3 years ago

4 0

RS,ST,TR IS THE ANSWER

You might be interested in

Which quadrilateral has four right angles and four sides of equal length?

olasank [31]

Answer:

Square.

Step-by-step explanation:

A square is a rectangle, but a rectangle is not a square.

8 0

2 years ago

Read 2 more answers

Indicate whether the following statement is true or false: An exponential growth function eventually exceeds a quadratic functio

Mariulka [41]

True

true true true

very true
∉∉

5 0

2 years ago

Read 2 more answers

321m ____ .0321 km Is it < > =

Neporo4naja [7]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Add. (3х – 4) + (4х – 6) А. 7х+ 10 В. 7х+2 C. 7х- 2 D. 7x - 10

LuckyWell [14K]

Answer:

Step-by-step explanation:

Because you have to do work

3 0

2 years ago

Which number line shows the solution set for |y-9| <12

RUDIKE [14]

Answer:

Option c

$y\geq-3$ or $y \leq 21$

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the inequation:

$|y-9| \leq 12$ has two cases

$(y-9)$ if $y \geq 9$ (i)

$-(y-9)$ if $y < 9$ (ii)

We solve the case (i)

$y \leq 9 + 12\\y\leq21$

We solve the case (ii)

$-y +9 \leq 12\\-y \leq 12-9\\y \geq -3$

Then the solution is:

$y\geq-3$ or $y \leq 21$

8 0

3 years ago