Answer:
$70,201.38
Step-by-step explanation:
To determine the principal amount, we can use the formula:

A = $200,000
r = 7% or 0.07
t = 15 years
n = 12
Now let's substitute our values.



So the principal needed to get 200,000 in 15 years is $70,201.38.
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
__
f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
__
g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
43 total movies the type of movies is added in to confuse you pay no ttention just add the total. he keeps 8 of them
43 - 8 = 35
he gives them to 5 friends
35 DIVIDED by 5 = 7
each friend would get 7 each
Answer:
315 ft^2
Step-by-step explanation:
276÷10 is 27.6 and that's the answer just draw that in long division or multiplication you should get 2,760