Answer:
15/2
Step-by-step explanation:
Hello,
the area of a triangle is b*h/2
we can set BC as the base because AC is harder to calculate.
Then we draw an imaginary height.
There's no way to really explain, but the height would be 5 here, since 3 - -2 = 5
The base is 3
3*5/2 = 15/2
Thanks,
lacampanella
Answer:
the answer is C. 210 sq. cm
Step-by-step explanation:
Find the area of the triangle
The area of one of the triangular faces can be found by using the formula below.
a = 1/2 bh
a = 1/2 (5 cm) (12 cm)
a = 30 sq. cm
Since there are two triangular faces, multiply the area of one triangular face by 2. The area of two triangular faces is 60 cm2.
Next, find the area of each of the three rectangular faces using the formula, area = lw.
1st rectangle
a = lw
a = (5 cm) (5 cm)
a = 25 sq. cm
2nd rectangle
a = lw
a = (5 cm) (12 cm)
a = 60 sq. cm
3rd rectangle
a = lw
a = (5 cm) (13 cm)
a - 65 sq. cm
Add the three rectangle areas to find a total of 150 sq. cm.
To find the surface area of the triangular prism, add the area of the two triangular faces to the area of the three rectangular faces.
60 sq. cm + 150 sq. cm = 210 sq. cm
n=2
8+8(8-n)=40+8n (distribute 8 through the parenthesis)
8+64-8n=40-8n (add the numbers)
<em>72-</em>8n=40+8n (move the variable to the left side and change its sign)
<em>72</em><em>-</em>8n+8n=40
-8n+8n=40<em>-72</em> (connect like terms)
-16n = -32 (divide both sides by -16)
<u><em>n=2</em></u>
Answer:
i got 178
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given equation:

Cube root both sides:
![\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7Bp%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\implies p= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20p%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:](https://tex.z-dn.net/?f=%5Ctextsf%7BApply%20exponent%20rule%7D%20%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3A)





Rewrite 8 as 2³:



Simplify:


