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charle [14.2K]
3 years ago
6

Simplify: 2(xy - 7) = [?] x = -1 and y = 3

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:2(xy-7)= -20

Step-by-step explanation:

Plug in -1 for x and 3 for 3, as the question says that x and y represent those values.

2(xy-7) = ?

2((-1)(3) - 7) = ?

2(-3-7)=?

2(-10)

-20

2(xy - 7) = -20

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lions [1.4K]

Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

5 0
3 years ago
Following are heights, in inches, for a sample of college basketball players. 78 83 82 78 78 80 81 79 79 83 77 78 84 82 80 80 82
blagie [28]

The mean height of the basketball players is 80.3 inches

For given question,

we have been given the list of heights, in inches, for a sample of college basketball players.

We need to find the mean height of the basketball players.

We know that, for given sample of data

mean = sum of all observations ÷ total number of observation

First we find the sum of given heights.

78 + 83 + 82 + 78 + 78 + 80+ 81 +79+ 79 +83+ 77 +78+ 84+ 82+ 80+ 80 +82+ 84+78+ 80 = 1606

Total number of observations = 20

Using the formula of mean,

⇒ mean height = 1606/20

⇒ mean height = 80.3 inches

Therefore, the mean height of the basketball players is 80.3 inches

Learn more about the mean here:

brainly.com/question/6813742

#SPJ4

3 0
1 year ago
Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
3 years ago
How do I do number 4?
Galina-37 [17]
What are you trying to find?
4 0
3 years ago
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Juli2301 [7.4K]
 the answer is 42.77...........................................
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3 years ago
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