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Brut [27]
3 years ago
6

Can anyone help me with this calc question?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

0.7048

Step-by-step explanation:

Use trap rule on the calc

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According to the graph above,what is the unit rate of a human's heartless per minute​
kari74 [83]

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3 years ago
Can someone help me please.​
wolverine [178]

9514 1404 393

Answer:

  a=\sqrt{33}

Step-by-step explanation:

The Pythagorean theorem tells you that the area of the square with side 'a' is the difference of the areas of the other two squares.

  a² = 7² -4²

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5 0
3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
PLEASE SOLVE DUE RIGHT NOW!!!!!!!!!!!!
erma4kov [3.2K]

Solution:

<u>We know that:</u>

Area \ of \ triangle = \dfrac{1}{2} \times Base \times Height

<em>Since we are already given the base and the height, we can substitute them into the formula to find the area of the triangle.</em>

Area \ of \ triangle = \dfrac{1}{2} \times 18 \times24

<u>Cancel out the "2" by dividing it by 18.</u>

Area \ of \ triangle =  9 \times24

<u>Simplify the multiplication.</u>

\bold{Area \ of \ triangle =  216 \ ft^{2}}

6 0
2 years ago
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