Y = 3x - 2....so we sub in 3x - 2 for y in the other equation
-3x + y = -2
-3x + (3x - 2) = -2
-3x + 3x = -2 + 2
0 = 0
there is infinite solutions to this problem
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
The slope of the line defined by the equation 3x-y=0 solution is 3 .
4/5,0.82,5/6
4/5 = .80
0.82
5/6 = 0.83
Answer:
m = p/5 -10
m= (p-50)/5
Step-by-step explanation:
What we practically want to here is to make m the subject of the formula.
Start by opening the brackets
P = 5m + 50
P-50 = 5m
Divide through by 5
(P-50)/5 = m
P/5 -50/5 = m
P/5 -10 = m
The option that looks probable is C ; M = (P-50)/5