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8090 [49]
3 years ago
8

Combine these radicals V27-V3​

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

2root3

Step-by-step explanation:

root27= root 3 x root9

= root3 x 3 -root3

= 3root3-1root3

= 2root3

You might be interested in
Find Percent increase or Percent Decrease
labwork [276]
300%? Since 50 minus 12.50 equals 37.5 and 12.50 times 300% equals 37.5 so if you add 12.50 and 37.50 it equals 50
6 0
3 years ago
Please help how do I do this
Dmitriy789 [7]

Answer:

a = 2.5
b = 4.33

Step-by-step explanation:

a = sin(30 degrees) = o/5 = 2.5
b = cos(30 degrees) = a/5 = (5root3) / 2 or about 4.33

verify using Pythagorean theorem
2.5^2 + 4.33^2 = 5^2
6.25 + 18.75 = 25
25 = 25

7 0
2 years ago
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

p = \frac{4}{6} = 0.6667

10 normal six sided dice are thrown.

This means that n = 10

Find the probability of obtaining at least 8 failures.

This is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951

P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867

P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174

Then

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0
3 years ago
Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)
vlabodo [156]

We know that \log_a(bc)=\log_a(b)+\log_a(c).

Using this rule,

\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3).

We also know that \log_c(a^b)=b\log_c(a).

Using this rule,

\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)

Now we know that \log_c(A)=2,\log_c(B)=5 so,

5\cdot2+3\cdot5=10+15=\boxed{25}.

Hope this helps :)

3 0
3 years ago
What is the answer to 5+(x−2)=−8
wlad13 [49]

Answer:

x= -11

Step-by-step explanation:

Use Math  way.

6 0
4 years ago
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