There are 250 sixth grade students at the school.
Step-by-step explanation:
Given,
Percent of sixth graders who like hip hop = 40%
Number of sixth graders who like hip hop = 100
Let,
x represent the total number of sixth graders at school.
Therefore;
40% of x = 100
![\frac{40}{100}*x=100\\0.40x=100](https://tex.z-dn.net/?f=%5Cfrac%7B40%7D%7B100%7D%2Ax%3D100%5C%5C0.40x%3D100)
Dividing both sides by 0.40
![\frac{0.40x}{0.40}=\frac{100}{0.40}\\x=250](https://tex.z-dn.net/?f=%5Cfrac%7B0.40x%7D%7B0.40%7D%3D%5Cfrac%7B100%7D%7B0.40%7D%5C%5Cx%3D250)
There are 250 sixth grade students at the school.
Keywords: percentage, division
Learn more about division at:
#LearnwithBrainly
Answer
+
=25
Step-by-step explanation:
the standard eqn of circle can be find as
(x-g)^2 + (y-h)^2=r^2
Part A= the starting point is in quadrant 2 and the finishing point is in quadrant 4
is say this because the starting points X and Y value is Neg,Pos there is only one quadrant that has Neg X and Pos Y and that is quadrant 2 and for the finishing point its X and Y value is Pos,Neg and there is only one quadrant that has Pos X and Neg Y and that is quadrant 4
Part A=starting point at quadrant 2 and finishing point at quadrant 4 explanation is above.
Part B= the starting point and the are checkpoint have the same Y and opposite but same X they are equally far form 0 but relative to the finishing point the checkpoint is closer by 2 units on the X axis and the starting point is farther by 2 units on the X axis
We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is
![x^{2} -y^2=20](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-y%5E2%3D20)
. Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is
![3x^2+y^2=124](https://tex.z-dn.net/?f=3x%5E2%2By%5E2%3D124)
. Let's solve the first equation for x^2:
![x^2=y^2+20](https://tex.z-dn.net/?f=x%5E2%3Dy%5E2%2B20)
and sub that value for x^2 into the second equation.
![3(y^2+20)+y^2=124](https://tex.z-dn.net/?f=3%28y%5E2%2B20%29%2By%5E2%3D124)
and
![3y^2+60+y^2=124](https://tex.z-dn.net/?f=3y%5E2%2B60%2By%5E2%3D124)
. Subtract 60 from both sides and combine the y^2 terms to get
![4y^2=64](https://tex.z-dn.net/?f=4y%5E2%3D64)
. Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it.
![x^2-16=20](https://tex.z-dn.net/?f=x%5E2-16%3D20)
, x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!