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2 years ago

What is the solution to the following system?

Mathematics

1 answer:

andrezito [222]2 years ago

8 0

Answer:

l think the problem of the is your work is not of the number l got.

x=2

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Find the constant of proportionality (r) in the equation y=rx

ahrayia [7]

Answer:

r = $\frac{1}{4}$

Step-by-step explanation:

Given the proportional equation

y = rx ← r is the constant of proportion

Divide both sides by x

$\frac{y}{x}$ = r

Use any ordered pair from the table.

Using (8, 2 ) , then

r = $\frac{2}{8}$ = $\frac{1}{4}$

8 0

2 years ago

Read 2 more answers

Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, aft

telo118 [61]

Answer:

Time t = 2 seconds

It will reach the maximum height after 2 seconds

Completed question;

Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:

H (t) = -(t-2)^2+9

many seconds after being thrown will the ball reach its maximum height?

Step-by-step explanation:

The equation of the height!

h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9

h(t) = -t^2 +4t -4+9

h(t) = -t^2 + 4t +5

The maximum height is at dh/dt = 0

dh/dt = -2t +4 = 0

2t = 4

t = 4/2 = 2

Time t = 2 seconds

It will reach the maximum height after 2 seconds

8 0

3 years ago

At the candy store there are 420 gumdrops and 280 chocolate bars, for a total of 700 candies all together. What is the ratio of

Mekhanik [1.2K]

Answer:

5 : 2

Step-by-step explanation:

Given that:

Number of gumdrops = 420

Number of chocolate bars = 280

Total Number of candies = 700

To find:

The ratio of candies to chocolate bars = ?

Solution:

First of all, let us discuss the method to find the ratio of any two quantities.

Suppose, we need to find the ratio of two numbers $p$ and $q$ .

Then to find the ratio $p:q$ , we need to divide p by q and represent it in the simplest form $\frac{a}{b}$ such that a and b can not be divided further.