The 1st term is 60.
Add 50 to this to get the 2nd term, 60 + 50 = 110.
Add 50 to that to get the 3rd term, 110 + 50 = 160.
Add 50 to that to get the 4th term, 160 + 50 = 210.
And so on...
Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.
In the 3rd, we ultimately added 2 copies of 50 to the 1st term.
In the 4th, we added 3 50s.
And so on... If the pattern continues, then the <em>n</em>-th term can be obtained by adding (<em>n</em> - 1) copies of 50 to the first term.
So, the 100th term is
60 + (100 - 1) * 50 = 5010
I am not sure but I think it’s c
44 - 12 = 32.
32g required
200
If the number is divisible by 5, then the last digit should be either 5 or 0.
First digit is fixed.
Second digit can be 10 ways.
Third digit can be 10 ways.
Fourth digit can be 2 ways.
So total number of digits 1 x 10 x 10 x 2 = 200
