The probability is 1/5.
<h3>
How to find the probability?</h3>
There are 3 red marbles and 3 white marbles, for a total of 6.
The probability that the first marble is red is:
P(red) = 3/6
The probability that the second marble is also red is:
P(red') = 2/5 (because now there are 2 red marbles and a total of 5).
The joint probability is:
P = (3/6)*(2/5) = 1/5
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the mean numbers of point scored is greater than 12 points(C.)
Answer:
Step-by-step explanation:
<u>Trapezoid</u>
The trapezoid has been broken into two triangles and a rectangle. The two triangles both have the same dimensions, so both have the area ...
A = (1/2)bh = (1/2)(2 m)(5 m) = 5 m²
The rectangle has area ...
A = bh = (2 m)(5 m) = 10 m²
So, the total area of the trapezoid is ...
trapezoid area = 5 m² +10 m² +5 m²
trapezoid area = 20 m²
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<u>Kite</u>
The kite has been broken into two triangles, so the area of each of them is ...
A = (1/2)bh
A = (1/2)(7 m)(3 m) = (21/2) m²
Then the area of the two halves of the kite will be ...
kite area = 2 × (21/2 m²)
kite area = 21 m²
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The area of the trapezoid is <u>1 m² less than</u> the area of the kite.
375 hamburgers were sold on Wednesday
<em><u>Solution:</u></em>
Let "h" be the number of hamburgers sold
Let "c" be the number of cheeseburgers sold
To find: number of hamburgers sold on Wednesday
Given that local hamburger shop sold a combined of 686 hamburgers and cheeseburgers on Wednesday
Therefore,
number of hamburgers sold + number of cheeseburgers sold = 686
h + c = 686 ------- eqn 1
There were 64 fewer cheeseburgers sold than hamburgers
Number of cheeseburgers sold = number of hamburgers sold - 64
c = h - 64 ------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
h + h - 64 = 686
2h - 64 = 686
2h = 686 + 64
2h = 750
h = 375
Thus 375 hamburgers were sold on Wednesday
Answer:
m= -
Step-by-step explanation: