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Tatiana [17]
3 years ago
14

2 ( 3x - 1) = -6x -2​

Mathematics
2 answers:
sp2606 [1]3 years ago
6 0

Answer: x=0

Step-by-step explanation:

if you are sloving fo x

2(3x-1) = -6x-2 cancel equal terms

6x-2=-6x-2 move the variable to the left

6x=-6x  collect like terms

12x=0 divide both sides

x=0

QveST [7]3 years ago
5 0

Answer:

6x -2 is the solved answer for the bracketed question.

Step-by-step explanation:

6x- 2 is not = to -6x -2

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Answer:

\huge \boxed{K=20}\checkmark

B. 20

Step-by-step explanation:

<em>First, you divide by 5 from both sides of equation.</em>

<em>\displaystyle \frac{5k}{5}=\frac{100}{5}</em>

<em>Simplify, to find the answer.</em>

<em>\displaystyle 100\div5=20</em>

<em>\huge \boxed{K=20}, which is our answer.</em>

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Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20}  \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}

Q2)

Apply phythogoras theorem:

CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4

Q3)

Apply phythogoras theorem again:

BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218}  \\\\BC=\sqrt{218} \\\\BC=14.76

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

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