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Tatiana [17]
3 years ago
14

2 ( 3x - 1) = -6x -2​

Mathematics
2 answers:
sp2606 [1]3 years ago
6 0

Answer: x=0

Step-by-step explanation:

if you are sloving fo x

2(3x-1) = -6x-2 cancel equal terms

6x-2=-6x-2 move the variable to the left

6x=-6x  collect like terms

12x=0 divide both sides

x=0

QveST [7]3 years ago
5 0

Answer:

6x -2 is the solved answer for the bracketed question.

Step-by-step explanation:

6x- 2 is not = to -6x -2

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Kim purchased white vases, red vases, and flowers to create centerpieces for an event. The flowers cost a total of $336 and each
laiz [17]

Option A:

I and III only the answers.

Solution:

Let white vases be "w" and red vases be "r".

Cost of total flower = $336

Cost of each vase = $11

Total cost of the centerpieces

                = Cost of (white vases + red vases)  + Cost of flowers

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                = 11w + 11r + 336

Total cost of the centerpieces = 11w + 11r + 336 = 11(w + r) + 336

Therefore I and III only the answers.

Option A is the correct answer.

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3 years ago
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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


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Answer:

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