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1 year ago

Please help V'W'is a translation of VW Write the translation rule.

Mathematics

1 answer:

wel1 year ago

4 0

Answer:

(x+11), (y+15)

Step-by-step explanation:

the point v gets translated 11 points to the right, so the translation is x+11.

Point v also gets translated 15 points up, so the translation is y+15

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4 is a BCA def of rectangle

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2 years ago

Which of the following statements are true about scalar multiplication of matrices?

Greeley [361]

Scalar multiplication of a matrix refers to the multiplication of all the elements of the matrix by an ordinary number which is called a scalar.

From the given options the statements which are true about scalar multiplication of matrices are;

a) You can multiply a matrix of any size by a scalar.

b) For any matrix A, 1 × A = A.

c) Scalar multiplication is a shortcut for repeated addition of the same matrix.

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3 years ago

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4. The system of equations 3x – 6y = 20 and 2x – 4y = 3 is

expeople1 [14]

3x - 6y = 20
-6y = -3x + 20
y = 1/2x - 20/6.....slope = 1/2...y int = -20/6 = -10/3

2x - 4y = 3
-4y = -2x + 3
y = 1/2x - 3/4..slope = 1/2...y int = -3/4

same slope, different y int = parallel lines = no solution = inconsistent

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3 years ago

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M= 2n - 2 solve for n

jasenka [17]

Answer: M=2n-2

2n-2=0

2n-2+2=0+2

2n=2

Divide both side by 2

n=1

Step-by-step explanation:

5 0

3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

2 years ago