Normalizing the bounds,
y=186, z = (186-200)/12 = -1.17
y = 210, z = (210 - 200)/12 = 0.83
We want the area of the standard normal between those. Looking it up in the cumulative table,
Ф(1.17) = 0.87900
Ф(0.83) = 0.79673
We need Ф(-1.17) which is 1 - Ф(1.17)
Then the probability we seek is
p = Ф(0.83) - Ф(-1.17) = Ф(0.83) + Ф(1.17) - 1 = 0.87900 + 0.79673 - 1 = 0.67573
Answer: 67.6%
Assuming f(x) is the cost and X is the number of months.
f(x)=2x+40
Answer:
f(15) is the area of the rectangular garden for a width of 15 ft
Step-by-step explanation:
we know that
where
x----> is the width of the rectangular garden
(2x+5) ----> is the length of the rectangular garden
so
f(15) -----> is the value of f(x) for x=15 ft
That means
f(15) is the area of the rectangular garden for a width of 15 ft
substitute the value of x and solve
Answer: Two answers: f=-3
f=3
Step-by-step explanation:
3(f-5)=6f-12+3f
3f-15=6f-12+3f
-15+12=6f+3f-3f
F=-3
Answer2
3(f-5)=6f-12+3f
3f-15=6f-12+3f
3f-6f+3f=-12+15
F=3
