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2 years ago

Well can somebody help me ‍♀️

Mathematics

1 answer:

Rasek [7]2 years ago

5 0

Yes, the new coordinates would be:

R': (9,9)
P': (3,3)
Q': (9,3)

You would multiply all of the current coordinates by three (its scale factor of enlargement) to obtain these answers. Hope this helps!

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PLZ HELP:

UkoKoshka [18]

1. In each graph, the two lines are parallel to each other.

2. Each set of equations have the same slope.

3. Equations that have the same slope as each other will always be parallel to each other.

8 0

2 years ago

What is 50% of the sum of the first 10 odd numbers

avanturin [10]

Answer:

Step-by-step explanation:

1+3+5+7+9+11+13+15+17+19= 100/2= 50

7 0

2 years ago

How to do!!!<br> please help

Margarita [4]

Step-by-step explanation:

Supplementary angle adds up yo 180°

So angle 2 is supplementary to angle 3

7 0

2 years ago

Read 2 more answers

How do I solve this?

vodomira [7]

I’m assuming what you’re asking here is how to *factor* this expression. For that, let’s rearrange the expression into a more familiar form:

-c^2-4c+21

From here, we’ll factor out a -1 so that we have:

-(c^2+4c-21)

Let’s focus on the quadratic expression inside the parentheses. To find our factors (c + x)(c + y), we’ll need to find two terms x and y that multiply together to make -21 and add together to make 4. It turns out that the numbers -3 and 7 work out perfectly for that purpose (-3 x 7 = -21 and 7 + (-3) = 4), so substituting them in for x and y, we have:

(c + (-3))(c + 7)
(c - 3)(c + 7)

And adding back on the negative from a few steps earlier:

-(c - 3)(c + 7)

7 0

2 years ago

The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe

UNO [17]

Answer:

The shark are fed $\frac16 \ ton$ of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = $\frac{2}{15}\ ton$

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = $\frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton$

Total fish fed in whole day = $\frac12 \ ton$

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = $\frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}$

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = $\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}$

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = $\frac{3-2}{6}=\frac16 \ ton$

Hence The shark are fed $\frac16 \ ton$ of fish during the night.

3 0

2 years ago