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ruslelena [56]
3 years ago
15

What is an explicit formula for the following recusive formula an=an-1+7;a1=2

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0
ANSWER
D.
EXPLANATION
The given explicit formula is

and

This implies that,

The explicit formula is given by:

We substitute the known values to get;
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1.Which of the following is equivalent to 0.00451
Finger [1]

Answer:

1)4.51×10^-3

2) .00632

Step-by-step explanation:

1.Which of the following is equivalent to 0.00451?

= \frac{451}{100000}

=\frac{4.51}{1000}

=\frac{4.51}{10^3}

= 4.51×10^-3

Therefore the answer is (a)

===================================================================

Which of the following is equivalent to 6.32 x 10-*3?

In order to find the answer to this question you can just put the notation into standard form which means they will be equivalent to each other.

The exponent is negative so you move to the left:

6.32=.00632

=.00632

Therefore 6.32*10^-3 is equivalent too (c) .00632

4 0
3 years ago
Read 2 more answers
Convert to scientific notation ​
andreev551 [17]

Answer:

8.245*10^6

Step-by-step explanation:

scientific notation is known as c*10^n

c : any number from 1-10

n : the power of base 10

the number in our case between 1 and 10 is 8.245

but then we want to move the decimal 6 spaces to the right, so we multiply that by 10^6

8 0
4 years ago
Find the median, mode and range:<br> 3, 3, 5, 7,8,9, 11<br> median<br> mode<br> range
sp2606 [1]

Answer:

median 7.5

mode 3

range 8

7 0
3 years ago
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What’s the midpoint of (-4,6) (4,-2)
valkas [14]

Answer:

(0,2)

Step-by-step explanation:

(\frac{x^{1} +x^{2} }{2} ,\frac{y^{1} +y^{2} }{2} )\\\\\frac{-4+4}{2}, \frac{6+-2}{2}\\ \\\frac{0}{2},\frac{4}{2}

(0,2)

Hope this helps!

8 0
4 years ago
What is the slope of the line passing through the points (1, -3) and (1,0)?​
blondinia [14]

Answer:

Undefined

Step-by-step explanation:

The formula for slope is [ y2-y1/x2-x1 ].

0-(-3)/1-1

3/0

Since the denominator is 0, the slope is undefined.

Best of Luck!

3 0
3 years ago
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