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Vlad [161]
3 years ago
15

On average, Seattle gets 38 inches of rain each year. How many centimeters of rain do they get each year?

Mathematics
1 answer:
Talja [164]3 years ago
8 0

Answer:

88.9

Step-by-step explanation:

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Michael writes down 4 different factors of 60
Marizza181 [45]

Answer:

34+(-12) =22

Step-by-step explanation:

because they said that adding numbers but they didn't said that negative Or positive. so i took those numbers

3 0
3 years ago
The path a character takes to navigate a level of a video game is given in the following graph.
KonstantinChe [14]

We want to find the domain for the graphed function. We will see that the correct option is A: -12 ≤ x ≤ 14

<h3>What is the domain of a function?</h3>

For a function f(x) we define the domain as the set of possible inputs that we can use in the function.

In this case, we need to see the values in the horizontal axis that the graph covers.

We can see that it goes from -12 to 14. We also can see that there are two jumps, at x = -6 and at x = 8, but these values belong to the graph (denoted by the black dot) meaning that these are in the domain.

Then the domain is:

-12 ≤ x ≤ 14

If you want to learn more about domains, you can read:

brainly.com/question/1770447

6 0
2 years ago
Find the measure of each bolded arc. Round to the nearest hundredth
vladimir1956 [14]

Answer:

Arc Length = 68.7

Step-by-step explanation:

The formula that is used to find the arc length:

s = (θ/360) * 2πr

(You would get the value of θ, by subtracting 57 from 360)

(You would get r by dividing 26 by 2)

Now we can solve this;

s = (303/360) 2π(13)

s = 0.842 * 2π(13)

s = 0.842 * 0.283(13)

s = 68.7

Hope this helps!

5 0
3 years ago
Wionna needs to average 5.8 from 14 judges. The mean score from 13 judges is 5.9. What is the lowest score she can receive from
kirill115 [55]
(5.9*13+s)/(13+1)\geq5.8

(76.7+s)/14\geq5.8

76.7+s\geq81.2

s\geq4.5
5 0
3 years ago
Read 2 more answers
Name two corresponding angles to &lt;1?
masya89 [10]
C
hope this helps :)
7 0
3 years ago
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