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Gre4nikov [31]
2 years ago
7

Let f(x)=12x^5-36x^4-6x^3 and g(x)=6x^2. Find f(x) over g(x)

Mathematics
1 answer:
Basile [38]2 years ago
6 0

Answer:

GCF = 6{x}^{3}6x

step 1. 6{x}^{3}(\frac{12{x}^{5}}{6{x}^{3}}+\frac{-36{x}^{4}}{6{x}^{3}}+\frac{-6{x}^{3}}{6{x}^{3}})

step 2. 6x3x6x3x12x5+6x3−36+4-6x3=3,888-32

step 3. 3,888-32=3,856

Step-by-step explanation:

your answer is 3,856 hope this helps

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General term for -13, -11, -9, -7
timurjin [86]

The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

<h3>Arithmetic progression</h3>

-13, -11, -9, -7

  • First term, a = -13
  • Second term = -11

Common difference, d = Second term - first term

= -11 - (-13)

= -11 + 13

= 2

Therefore,

Tn = a + (n - 1)d

Where,

  • n = number of terms

Tn = a + (n - 1)d

= -13 + (n - 1)2

= -13 - 2n - 2

Tn = -15 - 2n

So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

Learn more about arithmetic progression:

brainly.com/question/6561461

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2 years ago
PLEASE PLEASE HELP WITH RIGHT ANSWERS THANK YOU
Bogdan [553]
Just quit school bro it’s not worth it
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Whut is the soluton of when multiplying by 3
saveliy_v [14]
The answer of this is 3,6,9,12,15,18,21,24,27,30,33,36,39,...
4 0
3 years ago
The scale of a model train is 1 inch to 13.5 feet. One of the cars of the model train is 5 inches long. What is the length, in f
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Graph the equation (please hurry)
IrinaVladis [17]

<em>I</em><em> </em><em>have</em><em> </em><em>attached</em><em> </em><em>the</em><em> </em><em>graph</em><em>!</em><em> </em>

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

Here are some details about the equation and the graph!

Details of equation ⤵️

  • <u>The</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>written</u><u> </u><u>in</u><u> </u><u>slope-intercept</u><u> </u><u>form</u><u>.</u>
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Details of graph ⤵️

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  • <u>Vertical</u><u> </u><u>intercept</u><u> </u><u>=</u><u> </u><u>(</u><u>0</u><u>,</u><u>1</u><u>)</u>

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2 years ago
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