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3 years ago

Needhelpslovingthisproblem

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

Answer:

-4 to -1.5

Step-by-step explanation:

When the graph start to slope downwards or go down its decreasing. So when the hump starts to go down at (-4,0) it then starts to go up again after (-1.5,0). Hope this helps:)

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The perimeters of a rectangle and an equilateral triangle are equal. The length of the rectangle is twice the width, and the sid

Alex Ar [27]

Step-by-step explanation:

solution.

Let S represent side of the equilateral triangle.

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Therefore,if we let width to be represented by W

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2 years ago

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Yuliya22 [10]

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3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

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3 years ago