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krek1111 [17]
3 years ago
15

On a​ zip-line course, you are harnessed to a cable that travels through the treetops. You start at platform A and zip to each o

f the other platforms. How far do you travel from Platform B to Platform​ C? (Please add the EXPLANATION)

Mathematics
2 answers:
kari74 [83]3 years ago
8 0

Answer:

22.4 meters

Step-by-step explanation:

Because the distance and stuff I don't really know sorry

Shalnov [3]3 years ago
7 0

Answer:

We have to travel 26.93 units from platform B to C.

Step-by-step explanation:

Length of a segment having coordinates (x_1,y_1) and (x_2,y_2) is determined by the formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

From the graph attached,

Coordinates of the points B and C are (-25, -20) and (-15, 5) respectively.

Distance between these points B and C Or length of BC will be,

BC = \sqrt{(-25+15)^2+(-20-5)^2}

     = \sqrt{100+625}

     = \sqrt{725}

     = 5\sqrt{29}

     = 26.93 units

Therefore, we have to travel 26.93 units from platform B to C.

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Which values of x are solutions of the equation below
Mandarinka [93]

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Step-by-step explanation:

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4 0
3 years ago
How do you do this and what’s the answer to this I been stuck on this question for litterly 20 mins
Vsevolod [243]

\bf T=2\pi \sqrt{\cfrac{L}{g}}\implies \stackrel{\textit{squaring both sides}}{(T)^2=\left( 2\pi \sqrt{\cfrac{L}{g}}\ \right)^2}\implies T^2=2^2\pi^2\sqrt{\left( \cfrac{L}{g} \right)^2} \\\\\\ T^2=4\pi^2\cfrac{L}{g}\implies T^2=\cfrac{4\pi^2L}{g}\implies gT^2=4\pi^2L\implies g=\cfrac{4\pi^2L}{T^2}

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