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3 years ago

Write 134 in decimals

Mathematics

2 answers:

klio [65]3 years ago

8 0

Answer: 1.34

Step-by-step explanation: Can I get brainlest pls to level up

sweet-ann [11.9K]3 years ago

3 0

Answer:

1.34

Step-by-step explanation:

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In the algebra expression 7a+17b-10c,7, 17, and -10 are

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These numbers are categorized as numerical coefficients. A number that is next to a specific variable in an algebraic or polynomial expression and is essentially being multiplied to that variable.

6 0

3 years ago

10 ft

Gnom [1K]

Answer:

105.12 feets

Step-by-step explanation:

From the figure x we can identify a rectangle and a semicircle :

Area of rectangle = Length * width

Area = 8 * 10 = 80 feet²

The Area of a semicircle = 1/2πr²

Radius, r = 8 /2 = 4 feets

A = 1/2 * 3.14 * 4²

A = 3.14 * 8

A = 25.12 feet²

Area of figure = 80 + 25.12 = 105.12 feets

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3 years ago

Find the area of the figure shown below. 10 cm 5 cm 17 cm

stira [4]

Answer:

where is the figure?

Step-by-step explanation:

I can't see a figure

8 0

3 years ago

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When 4a-9b=22 and b= -2, what is the value of a? A.-10/3 B.-14/9 C.1 D.4 E.10

ycow [4]

4a-9b=22

substitute b=-2

4a -9(-2) = 22

4a +18 =22

subtract 18 from each side

4a = 4

divide by 4

a =1

Choice C

7 0

3 years ago

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The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

Write 134 in decimals​

Write 134 in decimals