Answer:
x^2 - 2xi - 4x +8i
Step-by-step explanation:
(x -4) (x -2i) (x+2i)
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>
Step-by-step explanation:
Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.
From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by
=
.
So, the population in the year t can be given by 
Population in the year 2000 =
=
Population in year 2000 = 3,762,979
Let us assume population doubles by year
.



≈
∴ By 2033, the population doubles.
Answer:
<h2>
4773 peoples.</h2>
Step-by-step explanation:
Given the number of people d, in thousands applying for medical benefits per week in a particular city c modeled by the equation d(t)=2.5 sin(0.76t+0.3)+3.8 where t is the time in years, the maximum number of people tat will apply will occur at d(t)/dt = 0
Differentiating the function given with respect to t, we will have;

First we need to know that differential of any constant is zero.

If
then;

To know the maximum number of people in thousands that apply for benefits per year in the city, we wil substitute the value of t = 29.75 into the modeled equation

Since d is in thousands, the maximum number of people in thousands will be 4.7732*1000 = 4773.2 which is approximately 4773 peoples.
Find the common denominator first--> 10
1/2= ?/10 ?=5
so 5/10 +9/10 (Now you just add the numerators and keep the common denominator the same)
14/10 and if you want to simplify it, simply divide both the top and bottom by 2
answer = 7/5
Answer:
i can't see the photo
Step-by-step explanation: