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andrey2020 [161]
3 years ago
7

una botella de agua con capacidad de 1 ½ contiene agua en sus ¾ partes ¿cuanta cantidad de agua contiene?

Mathematics
2 answers:
Ne4ueva [31]3 years ago
8 0
La cuatra botella de agua
harkovskaia [24]3 years ago
7 0
0.75 es la respuesta yo ya tenia esta respuesta
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GalinKa [24]
Can you put this in English so I can help you please
5 0
3 years ago
Read 2 more answers
I need help with this math
Zinaida [17]

Answer:

D

Step-by-step explanation:

∠1 + ∠2  =  180   {Supplementary angles}

6x + 15 + 3x + 3 = 180

6x + 3x + 15 + 3 = 180      

Combine like terms

9x + 18 = 180

Subtract 18 from both sides

9x = 180 - 18

9x = 162

x = 162/9

x = 18

∠2 = 3x +3

     = 3*18 + 3

     = 54 + 3

∠2 = 57°

8 0
2 years ago
Read 2 more answers
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
What is the exact volume of this cylinder? 4in 8in
MAVERICK [17]

The volume of the cylinder is; 128π in3

Base area(πr^2)*height

Π = 3.14

Therefore; 3.14 * 4^2 * 8

3.14 * 128

= 401.92 in3


4 0
3 years ago
HELP WILL MARK BRAINLIEST
bezimeni [28]

Answer:

2 by 4 is the answer have a great time

8 0
3 years ago
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