Simplify the following expression. 3m+4n-6n

How the transformations of the functions f(x)=15tanx and g(x)=tanx+15 differ?

Irina-Kira [14]

The transformation of f(x)=15tanx would be achieved by dilating y=tanx graph 15 times. This transformation will cause y'=15 y. This will increase the value of dilation become 15 times of the original

The transformation of g(x)=15tanx would be achieved by shifting y=tanx graph 15 right. This transformation will cause x'=x+15. This will change the value from tan x into tan(x+15)

3 0

2 years ago

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Write a polynomial in standard form with given Zeroes given zeroes are 5 and 3+2i

Neko [114]

Required potynomial = (x -5)(x - 3 - 2i)(x - 3 + 2i) = (x - 5)(x^2 - 6x + 13) = x^3 - 6x^2 + 13x - 5x^2 + 30x - 65 = x^3 - 11x^2 + 43x - 65

4 0

3 years ago

Joe works as a busboy making $7 per hour and as a theater usher making $9 per hour. Let b be the number of hours he works as a b

Vilka [71]

Answer:

The inequality describing the situation is:

$7b+9u>1500$

Step-by-step explanation:

Joe works as a busboy at the rate of = $7 per hour

Let the number of hours he works as a bus boy this month be = $b$ hours

∴ Amount Joe would make this month working as a busboy = $\$7\times b=\$7b$

Joe works as a theater usher at the rate of = $9 per hour

Let the number of hours he works as a theater usher this month be = $u$ hours

∴ Amount Joe would make this month working as a theater usher = $\$9\times u=\$9u$

Total amount Joe would make this month = $\$(7b+9u)$

His goal is earn more than $1500 this month.

∴ The situation can be represented in the following inequality:

$7b+9u>1500$

6 0

2 years ago

Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did

svetoff [14.1K]

I added a screenshot with the complete question

Answer:
Total miles = 2.5 miles

Explanation:
1- While walking:
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked $\frac{20}{60} = \frac{1}{3}$ of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
Substitute with the givens to get the distance she covered while walking:
Distance = 3 * $\frac{1}{3}$ = 1 mile

2- While running:
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran $\frac{15}{60} = \frac{1}{4}$ of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
Substitute with the givens to get the distance she covered while running:
Distance = 6 * $\frac{1}{4}$ = 1.5 miles

3- getting the total mileage:
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

4 0

3 years ago

I’m bored somebody plz talk to me

Molodets [167]

Answer:

hi, how are you?

Step-by-step explanation:

thanks for the free points, btw :)

4 0

2 years ago

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