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3 years ago

What does 2.8- 4.4n- 2n + 7 equal?

Mathematics

2 answers:

Dennis_Churaev [7]3 years ago

7 0

i believe it equals 9.8-6.4n

sorry, im not very good at explaining how i solved it!! D:

but i hope this helped you out :)

boyakko [2]3 years ago

5 0

Answer:

2.8- 4.4n- 2n + 7 = -6.4n + 9.8

Step-by-step explanation:

combined like term:

-4.4n - 2n = -6.4n

2.8 + 7 = 9.8

so all you do is combined together and got -6.4n + 9.8

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Determine the 16th term of the sequence 9, 18, 36.... r________?

raketka [301]

Answer:

$a = 9 \\ d = 9 \\ a_{16} = a + 15d = 9 + 15 \times 9 = 9 + 135 \\ = > a_{16} = 144 \\ = = = = = = = = = =$

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3 years ago

If Ben goes on a 6-day hike and travels 2 miles each day, how far will he go altogether?

gizmo_the_mogwai [7]

Answer:

12 miles

Step-by-step explanation:

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3 years ago

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Which expression represents 81 decreased by an unknown number?

Bogdan [553]

Answer: Choice A

Step-by-step explanation:

The correct answer is choice A. The equation 81 - a is doing exactly what the question is asking for. It represents 81 minus an unknown number, with the unknown number being shown as a.

4 0

3 years ago

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Ma= P2-P1/t solve for p1

natulia [17]

Answer:

P1 = P2 - ma*t

Step-by-step explanation:

ma= P2-P1/t

we multiply by t both sides of the equation

ma*t = (P2 - P1)*t/t

ma*t = P2 - P1

we sum by P1 both sides of the equation:

P1 +ma*t = P2 - P1 +P1

We ave:

P1 + ma*t = P2

we subtract by ma*t both sides of the equation:

P1 + ma*t -ma*t = P2 - ma*t

finally we have:

P1 = P2 - ma*t

3 0

3 years ago

1+cos2A /1-cos2A=cotA.cotA

Allisa [31]

Answer:

See Explanation

Step-by-step explanation:

$formulae \: to \: be \: used : \\ \cos 2 \theta = 2 { \cos}^{2} \theta - 1 \\ and \\ \cos 2 \theta = 1 - 2 { \cos}^{2} \theta \\ \\ now \: let \: us \: prove \: the \: given \: trigonometrical \: \\ identity. \\ \\ \frac{1 + \cos2A}{1 - \cos2A} = \cot \: A. \cot \: A \\ LHS = \frac{1 + \cos2A}{1 - \cos2A} \\ \\ = \frac{1 +2 { \cos}^{2} A- 1 }{1 - (1 - 2 { \sin}^{2} A)} \\ \\ = \frac{1 +2 { \cos}^{2} A- 1 }{1 - 1 + 2 { \sin}^{2} A} \\ \\ = \frac{2 { \cos}^{2} A }{2 { \sin}^{2} A} \\ \\ = \frac{{ \cos}^{2} A }{ { \sin}^{2} A} \\ \\ = { \cot}^{2} A \\ \\ = { \cot} A .{ \cot} A \\ \\ = RHS \\ \\ hence \: proved.$

6 0

3 years ago