The formula for an area of a circle is A= pi(r)^2
so if you plug in 5 to r (because it’s the radius) you should get A= 78.5
The length of JK rounded to the nearest hundredth is 4.72
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
area of square = 4ft²
a s area of square = length×lenght
let lenght =x
so area = x²
x²= 4ft²
taking square root
x=2 ftSo lebght of each side is 2 ft.
If we consider each alphabet is at 1 unit, then U is at a distance of 1 unit and X is at a distance of 4 units . To find the scale factor, we need to see 1 multiply by what is equal to 4. And 1*4=4
So the scale factor is 4 . And the answer is 4 .
