Personally the easiest way for me is to first find the area of the rectangle and take away the missing triangles. So assuming it’s a rectangle we get (4+5)(3+2) = 45. Ok now we find the area of the triangles. 0.5(4)(3) = 6. Now we subtract that twice from our 45.
45-6-6 = 33. The answer is 33
Answer:
i think the question is incomplete but
Tina at an average contains each package of
50 sheets ÷ 8 pack
6.205 of sheet in each pack
125 sheets ÷ 3 packs
caz contain at average 41.60 sheet average
but where the juan packs of paper that's why question is incomplete
Answer: 70.5°
Solution:
Call B, the measure of the angle CBA
cos(B) = adjacent-leg / hypotenuse = 3 / 9 = 1 / 3
=> B = arc cos (1/3) ≈ 70.5°
I will calculate other measures for you, trying to cover the most common ratios: sine, cosine, tangent
1) (segment CA)^2 + (segment BC)^2 = (hypotenuse)^2
=> (segment CA )^2 = (hypotenuse)^2 - (segment BC)^2 = 9^2 - 3^2 = 81 - 9 = 72
=> segment CA = √72 = 6√2
2) sin(B) = opposite-leg / hypotenuse = 6√2 / 9 =2√2 / 3
3) sin(A) = cos(B) = 1/3
4) cos(A) = sin(B) = 2√2 / 3
5) tan(B) = opposite-leg / adjacent-leg = (2√2 / 3 ) / 3 = 2√2 / 9
6) tang(A) = 3 / (2√2 /3) = 9 /( 2√2) = 9√2 / 4
By doing something like 56 lowest and 89 highest then do 89-56 the range us 33
