So x times y=15
x+y=12
solve
x+y=12
subtract x from both sides
y=12-x
subsitute
xy=15
x(12-x)=15
distribute
12x-x^2=15
subtract (12x-x^2) from both sides
0=x^2-12x+15
use quadratic formula which is
x=
where you have
0=ax^2+bx+c
so
a=1
b=-12
c=15
subsitute
x=
x=
x=
x=
x=6+/-
x=6+
or 6-
or aprox
x=10.5826 or 1.41742
the numbers are 10.5826 and 1.41742
None of the above is the correct answer.
4(-52+2)= -208+8, which equals -200.
-200+-6=-206
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
Answer:
C is the answer
Step-by-step explanation:
Its An experimental study that is a statistical study because it provides the researcher drawing back statistics from the children and its experimental because its based off of an experiment