How much dose acute angle have

Evaluate the following expression. 2^-2<br> Answer needs to be a fraction

Shtirlitz [24]

Answer is.........: 1/4

7 0

3 years ago

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What is the circumference of the circle if r = 3,5 feet?

Nady [450]

Answer:

21.98

Step-by-step explanation:

C=2πr C=2d are the formulas of circumference so that would mean the diameter of the circle is 7 since 2 times the radius is the diameter. We then multiply the diameter 7 by PI to get 21.98

8 0

3 years ago

John shot a toy rocket into the air. Consider the graph below which shows the relationship between the height of the rocket from

EleoNora [17]

<h2>The height of the rocket increases for some time and then decreases for some time.</h2>

The height from the ground increases from 4 to 26, then decreases from 26 to 0.

Why the others are wrong.

A. The height of the rocket changes at a constant rate for the entire time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

C. The height of the rocket remains constant for some time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

D. The height of the rocket decreases for some time and then increases for some time.

This implies the graph decreases first then increases. However, the rocket will increase, then decrease.

5 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

Which Situation has a greater Rate of Change?<br> A: f(x) = 2(5)*<br> B: f() = 5(2)

Ivanshal [37]

Answer:

B

Step-by-step explanation:

Since 2 is the constant on A and 5 on B and 5's multiples are greater then 2's

7 0

3 years ago