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soldi70 [24.7K]
2 years ago
9

Identify the factors of x2 − 5x − 24.

Mathematics
1 answer:
vladimir2022 [97]2 years ago
7 0
(x-8)(x+3) here we go.
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If f(x)=3x-6 then find f(4)
masya89 [10]

Answer:

f(4) = 6

Step-by-step explanation:

f(x) = 3x - 6

f(4) = 3(4) - 6

f(4) = 12 - 6

f(4) = 6

8 0
3 years ago
a city that has an elevation of 15 meters is closer to sea level than a city with an elevation of -10 true or false? explain you
12345 [234]

Answer:

False

Step-by-step explanation:

At sea level, elevation is 0. This means that we can portray sea level as being the midpoint of distances below sea level and distances above sea level.

Thus, a distance of 1 m below sea level = - 1 is equivalent to a distance of 1 m above sea level albeit in opposite directions.

Hence, an elevation of 15m above sea level is greater in distance Than an elevation of - 10 m below sea level because the absolute value of 15 is greater than the absolute value of 10.

|15 - 0|= 15

|-10 - 0| = 10

Hence, elevation of - 10 below Sea level is closer to sea level than elevation of 15 above sea level

5 0
2 years ago
a bamboo plant grows 62 and 1/2 in in 1 1/4 months what is the bamboo growth rate in inches per month​
Murljashka [212]

Answer:

.4 in or 2/5 in per month (.4 and 2/5 means the same one is in decimal and the other one is in fractions.

4 0
3 years ago
Please help iam lost
Goryan [66]

Answer:

x = 4.

Step-by-step explanation:

I am assuming that you want to find the values of x and that WXYZ is a parallelogram.

In a parallelogram opposite sides are equal, therefore:

11x + 1 = 19x - 31

1 + 31 = 19x - 11x

32 = 8x

x = 32/8 = 4.

6 0
3 years ago
A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
2 years ago
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