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3 years ago

What is p−m ÷ p−n equal to

Mathematics

1 answer:

jekas [21]3 years ago

6 0

Answer:

$\frac{P-M}{P-N}$ cancel out the p and it is Negative m/negative n

Step-by-step explanation:

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Step-by-step explanation:

y-(-4)= 7/4(x-(-4)

Y+4= 7/4x +4

Y = 7/4x

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What is the maximum r-value for the polar equation r = -3 + 5 sin theta? Note that a maximum r-value is a maximum value of (r),

kipiarov [429]

Answer:

Step-by-step explanation:

The given equation, r = -3 + 5 sin theta, includes a sine term whose max value is +5 and whose min value is -5. We are interested in finding the max value that r can have. To obtain this, take that constant term, -3, and add teh max value of the sine function, which is +5. Net: 5 - 3 = 2.

The max value that r = -3 + 5 sin theta can take on is +2.

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3 years ago

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Coins are produced at the United States mint in Philadelphia. If the mint can make 45,000 coins each hour. How many coins can it

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3 years ago

The probability that a randomly selected teenager watched a rented video at least once during a week was 0.75. What is the proba

Whitepunk [10]

Answer:

There is a 75.65% probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week.

Step-by-step explanation:

For each teenager, there are only two possible outcomes. Either they watched a rented video at least once during a week, or they did not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that a randomly selected teenager watched a rented video at least once during a week was 0.75. This means that $p = 0.75$ .

What is the probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week?

Group of 7, so $n = 7$ .

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7)$ .

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{7,5}.(0.75)^{5}.(0.25)^{2} = 0.3115$

$P(X = 6) = C_{7,6}.(0.75)^{6}.(0.25)^{1} = 0.3115$

$P(X = 7) = C_{7,7}.(0.75)^{7}.(0.25)^{0} = 0.1335$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) = 0.3115 + 0.3115 + 0.1335 = 0.7565$ .

There is a 75.65% probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week.

3 0

3 years ago