8x-10y=-23
9x+10y=-16
(8x+9x)+(10y-10y)=(-23+(-16))
17x+0y=-39
x=-39/17
8(-39/17)-10y=-23
-312/17-10y=-23
-10y=-23+312/17
-10y=-79/17
y=79/170
Answer:
1) g ≥ 17
2) g > -10
3) g > -1
Step-by-step explanation:
1) 7 (g-19) ≥ -14 divide both sides by 7
g - 19 ≥ -2 add 19 to both sides
∴ g ≥ 17
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2) 3(7g+17) > -19 + 14g
21g + 51 > -19 + 14g
21g - 14g> -19 - 51
7g > -70
g > -10
========================================
6(-6g+6) > -2(19g-17)
-36g + 36 > -38g + 34
-36g + 38g > 34 - 36
2g > -2
g > -1
========================================
M= (7-1)/(2-0)=3
y=3x + c
plug in Q
1= 3 x 0 +c
=> c =-2
=> the equation represents line QR is y=3x -2
Answer:
The following option is not correct:
(a) If 100 numbers are generated comma each integer between 0 and 99 must occur exactly once.
Step-by-step explanation:
This is not correct, as there is a possibility of an integer being generated twice when 100 numbers are generated.
This can be explained with an example such as stated below:
3 numbers are to be generated.
The number generated can either be 1, 2, or 3.
The probability for all three numbers to be generated once when the generator is run 3 times is:
(1/3)*(1/3)*(1/3) * Number of ways to arrange the three numbers
Thus this probability will be:
Probability = (1/3)^3 * 3!
Probability = 0.222
Since the probability here is not equal to 1, the probability for the same thing happening at a larger scale will also not be 1.
