Okay, notice one thing right off the bat? 60 degrees on a right triangle (unit circle w/ terminal arm) will create the infamous 30-60-90 triangle.
We can use this to our advantage. Since sin is the y-coordinate on the unit circle. We need to solve for the longest side of a 30-60-90 triangle.
We find that the long side (y) of our 30-60-90 triangle is sqrt(3)/2. Since this is in quadrant 1, we know it is positive.
So -- sin60° = sqrt(3)/2
Answer:
-4b^3 + b^2
Step-by-step explanation:
I think the answer should be A correct me if I’m wrong tho
All ya got to do is break is down
Step 1) 4y(2y2+3y-5)-3(2y2+3y-5)
Step 2) 8y3+12y2-20y-3(2y2+3y-5)
Step 3) 8y3+12y2-20y-(6y2+9y-15)
Step 4) 8y3+12y2-20y-6y2-9y+15
Step 5) 8y3+(12y2-6y2)+(-20y-9y)+15
Then you got to simplify and you have to
Leave the
8y3 +
12-6= number y2 -
-20-9=- number y
Then leave the 15
Sorry your doing the same math as me so I get carried away :p
Answer:
Distance farther the Kangaroos need to go to cover a mile = 780 feet
Step-by-step explanation:
Given:
Kangaroos cover 30 feet in a single jump.
Kangaroos can make such jumps 150 times in a row.
To find the distance farther it needs to go to cover a mile.
Solution:
Using unitary method to find distance covered by kangaroos in a row.
If in a single jump Kangaroos cover = 30 feet
So, in 150 jumps it will cover =
= 4500 feet
We know 1 mile = 5280 feet
Thus, distance farther the Kangaroo needs to go to cover a mile will be =
= 780 feet