What you have to do is balance the chemical equations to make sure everything is even on both sides. If you want me to help you answer the questions comment back
I’m pretty sure it’s B
Hope that helps
Answer:
the value of molar absorptivity is 229000 
Explanation:
given data
phenol phthalein solution = 0.050 g
total volume = 100.0 ml
dilute = 100.0 ml
diluted sample = 0.18
solution
we get here concentration that is express as
concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1
put here value
concentration =
concentration = 0.00157 M
and here dillution equation is express as
c1 × v1 = c2 × v2 .................2
here c1 and c2 is initial and final concentration
and v1 and v2 is initial and final volume
put here value
0.001571 × 0.050 = c2 × 100
c2 = 7.855 ×
M
and
now we get molar by absorbance equation that is
A = E × C × l ................3
here A is absorbance and E is molar and c is absorptivity and l is path length
put here value
0.18 = E × 7.855 ×
× 1
E = 229000 
Answer:

Explanation:
Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.
- The change in temperature is the difference between the initial temperature to the final temperature.
- The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
- ΔT= final temperature - initial temperature
- ΔT= 67°C - 23°C
- ΔT= 44°C
Now we know all the values.
- m= 26.3 g
- c= 0.930 J/g °C
- ΔT= 44°C
Substitute the values into the formula.

Multiply the first two numbers together. The units of grams cancel.

Multiply again. This time, the units of degrees Celsius cancel.

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.
Answer:
-605,5 kJ/mol of energy
Explanation:
Combustion of CH₄, CO and H₂ are:
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH = -890 kJ/mol
CO(g) + ¹/₂O₂(g) → CO₂(g) ΔH = -283 kJ/mol
H₂(g) + ¹/₂O₂(g) → H₂O(l) ΔH = -286 kJ/mol
The heat combustion of methane gives <em>-890 kJ/mol </em>of energy. The water gas gives the average of energy between the reactions, that is:
-283kJ/mol -286kJ/mol /2 = <em>-284,5 kJ/mol of energy</em>
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Difference between the two values is:
-890kJ/mol - (-284,5kJ/mol) = <em>-605,5 kJ/mol of energy</em>
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I hope it helps!