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notsponge [240]
3 years ago
8

HELP ASAP!! If a liquid substance is transferred to a different container, what can be predicted about the volume of the liquid

in the new container? A. This cannot be predicted. B. The volume will decrease. C. The volume will stay the same. D. The volume will increase.
Chemistry
2 answers:
RSB [31]3 years ago
7 0

Answer:

C

Explanation:

The volume stays the same no matter the container its in

Elanso [62]3 years ago
6 0

Answer:

C. The volume will stay the same

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How do i solve these chemistry problems
Ivahew [28]

What you have to do is balance the chemical equations to make sure everything is even on both sides. If you want me to help you answer the questions comment back

8 0
3 years ago
Which part of an atom is mostly empty space?
Brilliant_brown [7]
I’m pretty sure it’s B

Hope that helps

7 0
3 years ago
A stock phenolphthalein solution was prepared by dissolving 0.050 g in a total volume of 100.0 ml. You place one drop (0.050 ml)
devlian [24]

Answer:

the value of molar absorptivity is 229000 M^{-1} cm^{-1}

Explanation:

given data

phenol phthalein solution = 0.050 g

total volume = 100.0 ml

dilute = 100.0 ml

diluted sample = 0.18

solution

we get here concentration that is express as

concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1

put here value

concentration = \frac{0.050\times 1000}{318.32\times 100}    

concentration = 0.00157 M

and here dillution equation is express as

c1 × v1 = c2 × v2   .................2

here c1 and c2 is initial and final concentration

and v1 and v2 is initial and final volume

put here value  

0.001571 × 0.050 = c2 × 100

c2 = 7.855 × 10^{-7} M

and

now we get molar by absorbance equation that is

A = E × C ×  l   ................3

here A is absorbance and E is molar and c is absorptivity and l is path length

put here value

0.18 = E × 7.855 × 10^{-7}  × 1

E = 229000 M^{-1} cm^{-1}

3 0
3 years ago
How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
Water gas (a mixture of carbon monoxide and hydrogen) is prepared by passing steam over red-hot coke: C(s) + H2O(g) → CO(g) + H2
Tresset [83]

Answer:

-605,5 kJ/mol of energy

Explanation:

Combustion of CH₄, CO and H₂ are:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)   ΔH = -890 kJ/mol

CO(g) + ¹/₂O₂(g) → CO₂(g) ΔH = -283 kJ/mol

H₂(g) + ¹/₂O₂(g) → H₂O(l) ΔH = -286 kJ/mol

The heat combustion of methane gives <em>-890 kJ/mol </em>of energy. The water gas gives the average of energy between the reactions, that is:

-283kJ/mol -286kJ/mol /2 = <em>-284,5 kJ/mol of energy</em>

<em />

Difference between the two values is:

-890kJ/mol - (-284,5kJ/mol) = <em>-605,5 kJ/mol of energy</em>

<em />

I hope it helps!

5 0
3 years ago
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