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pickupchik [31]
3 years ago
5

How is an elements outer electron configuration related to its position in the periodic table?

Chemistry
1 answer:
Umnica [9.8K]3 years ago
7 0
Well, if you look at group 1 of the periodic table, you will notice a thrend. All elements in group 1 have 1 valence / outer electron. Then you look at period 2, 3, 4 and so on, you will see that the group number corresponds the number of valence/ outershell electrons. Hence, the group determines the electron(s) on the outershell.
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What mass in grams of hydrogen is produced by the reaction of 4.73 g of magnesium with 1.83 of water
Luba_88 [7]

The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams

<h3>Stoichiometric calculations</h3>

From the balanced equation of the reaction:

Mg + 2H_2O -- > Mg(OH)_2 + H_2

The mole ration of magnesium to water is 1:2.

Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles

Mole of 1.83 grams water = 1.83/18 = 0.102 moles

Hence, water is limiting.

Mole ratio of water to the hydrogen produced = 2:1

Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles

Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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2 years ago
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natka813 [3]

Answer:

the mass of one mole of an element, or Avogadro's number (6.02 x 1023) of atoms, is equal to its atomic mass in grams. In other words, 1 amu = 1 gram/mole. So if the mass of one hydrogen atom is 1 amu, the mass of one mole of hydrogen is 1 gram.

Explanation:

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