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pickupchik [31]
3 years ago
5

How is an elements outer electron configuration related to its position in the periodic table?

Chemistry
1 answer:
Umnica [9.8K]3 years ago
7 0
Well, if you look at group 1 of the periodic table, you will notice a thrend. All elements in group 1 have 1 valence / outer electron. Then you look at period 2, 3, 4 and so on, you will see that the group number corresponds the number of valence/ outershell electrons. Hence, the group determines the electron(s) on the outershell.
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Which species can conduct an electric current?<br> 1) NaOH<br> 2) NaCl<br> 3) H2O<br> 4) HCl
Stells [14]

Answer:

4) HCI

Explanation:

HCI is a strong acid.

7 0
3 years ago
In what way is the Moon like the Earth?
Svetlanka [38]

Answer:

The Moon has an atmosphere.

Explanation:

The Moon has an atmosphere, but it is very tenuous. Gases in the lunar atmosphere are easily lost to space. Because of the Moon's low gravity, light atoms such as helium receive enough energy from solar heating so that they escape in just a few hours.

5 0
3 years ago
A constant-volume calorimeter was calibrated by carrying out a reaction known to release 3.50 kJ of heat in 0.200 L of solution
Dmitrij [34]

Answer:

The change in internal energy is - 1.19 kJ

Explanation:

<u>Step 1:</u> Data given

Heat released = 3.5 kJ

Volume calorimeter = 0.200 L

Heat release results in a 7.32 °C

Temperature rise for the next experiment = 2.49 °C

<u>Step 2:</u> Calculate Ccalorimeter

Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C

Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C

<u>Step 3:</u> Calculate energy released

Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ

<u>Step 4:</u> Calculate change in internal energy

ΔU =  Q + W       W = 0  (no expansion)

Qreac = -Qcal = - 1.19 kJ

ΔU = - 1.19 kJ

The change in internal energy is - 1.19 kJ

4 0
4 years ago
The chemical formula for the initial sample is mnso4·h2o and the chemical formula for the final sample is mnso4. use their molec
sammy [17]
The initial sample has a molecular formula of MnSO₄·H₂O. This molecule is a hydrate as it has a unit of water within its structure for every molecule of MnSO₄. This sample is being dehydrated to remove the water to give.

MnSO₄·H₂O → MnSO₄ + H₂O

MnSO₄·H₂O has a molecular mass of 169.02 g/mol. While MnSO₄ has a molecular mass of 151 g/mol. Water has a molecular mass of 18.02 g/mol. We now can use the ratio of the mass of water to the mass of the initial sample to determine the percentage of each component by mass.

% water by mass:

18.02/169.02 x 100% = 10.7% Water by mass.

% MnO₄ by mass:

151/169.02 x 100% = 89.3% MnSO₄ by mass.

Water makes up 10.7% of the initial mass of MnSO₄·H₂O.
4 0
3 years ago
Fluorine gas reacts violently with water to produce HF and ozone
serious [3.7K]

Answer:

c8.3 moles

Explanation:

5 0
3 years ago
Read 2 more answers
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