Ask question

Ask question

All categories

2 years ago

9

How much heat (kj) is required to convert 3.12 moles of liquid benzene at 75.1Â°c to gaseous benzene at 115.1Â°c?

1 answer:

Tems11 [23]2 years ago

3 0

The total energy includes sensible heat to raise the temperature from 75.1°C to the boiling point. It also includes the latent heat to convert the liquid to gas. Then, it also includes sensible heat from he boiling point to 115.1°C. The equation is:

Energy = nCp,liquid(T,bp - T₁) + nΔH + nCp,gas(T₂ - T,bp)
where
n is the number of moles
T,bp is the boiling point of benzene at 80.1°C
Cp,liquid = 134.8 J/mol·°C
Cp,gas = 82.44 J/mol·°C
ΔH = 87.1 J/mol

Energy = (3.12 moles)(134.8 J/mol·°C)(80.1°C - 75.1°C) + (3.12 moles)(87.1 J/mol) + (3.12 moles)(82.44 J/mol·°C)(115.1°C - 80.1°C)
Energy = 11,377.08 J

You might be interested in

Write the answer in scientific notation when you multiply 2 x 104 by 3 x 104.

emmasim [6.3K]

Answer:

6× 10⁸

Explanation:

We need to find the multiplication of 2 x 10⁴ by 3 x 10⁴.

2 x 10⁴ × 3 x 10⁴

= (3 × 2) x 10⁴ x 10⁴

= 6 x 10⁴ x 10⁴

= 6 × 10⁴⁺⁴

= 6× 10⁸

Hence, the required answer is 6× 10⁸.

7 0

2 years ago

How many liters of C3H6O are present in a sample weighing 25.6 grams?

lawyer [7]

To Find :

Number of moles of C₃H₆O present in a sample weighing 25.6 grams.

Solution :

Molecular mass of C₃H₆O is :

M = (6×12) + (6×1) + (16×1) grams

M = 94 grams/mol

We know, number of moles of 25.6 grams of C₃H₆O is :

$n = \dfrac{Given \ Mass \ Of \ C_3H_6O }{Molar\ Mass \ Of \ C_3H_6O }\\\\n = \dfrac{25.6}{94}\ mole\\\\n = 0.27 \ mole$

Hence, this is the required solution.

4 0

2 years ago

How many gallons of gasoline that is 5% ethanol must be added to 2,000 gallons of gasoline with no ethanol to get a mixture that

Amanda [17]

Answer:

$V_1= 3000 gal$

Explanation:

We have 3 solutions:

Solution 1 (with ethanol)
Solution 2 (no ethanol)
Final solution

$V_f=V_1 + V_2$

and for the ethanol:

$V_f*0.03=V_1*0.05 + V_2*0$

$V_f=V_1 \frac{5}{3}$

Combining:

$V_1 \frac{5}{3}=V_1 + V_2$

$V_1 \frac{2}{3}= V_2$

$V_1= \frac{3}{2} V_2$

If V2=2000 gal:

$V_1= \frac{3}{2} 2000 gal$

$V_1= 3000 gal$

8 0

3 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

Explanation:

Wavelength of the photon emitted = $\lambda =646.3 nm =646.3\times 10^{-9} m$

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

$E=\frac{hc}{\lambda }$

h = Planck's constant = $6.626\tiomes 10^{-34} Js$

c = Speed of the light = $3\times 10^8 m/s$

$E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}$

$E=3.07\times 10^{-19} J$

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

3 0

3 years ago

10 What is a characteristic of all living organisms?

Vladimir [108]

Answer:

D - ingestion

Explanation:

7 0

2 years ago

Read 2 more answers