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bazaltina [42]
3 years ago
15

For a two-tailed test with a sample size of 20 and a .20 level of significance, the t value is _____. Selected Answer: d. 1.328

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

1.328

Step-by-step explanation:

Given :

Sample size, n = 20.

Degree of freedom, df = n - 1

df = 20 - 1 = 19

α = 0.2

Using the T-distribution calculator :

Since it is two - tailed:

Tα/2 ; 19 = T0.2/2 ; 19 = T0.1, 19 = 1.3277 = 1.328

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Jordan is stacking 2 boxes on a shelf. The bottom box measures 7 inches​ long, 6 inches​ wide, and 6 inches high. The top box is
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Answer: 377

Explanation: Length x width x height
7x6 = 42 x 6 = 252
A cube means all sides a equal. So 5x5x5 = 125
Add both together and you get 377 cubic inches.
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18 units.

Step-by-step explanation:

A classic right triangle is the 3, 4, 5 triangle. Essentially, 3^2 + 4^2 = 5^2 . Otherwise known as, 9 +16 = 25. With that said, there are two of those that we can make by drawing horizontal lines along the grid. We also know from counting the two vertical sides are each 4 units. To summarize, two sides are 5 units and two are 4 units. We add them together, 5 + 5 + 4 + 4 = 18

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51%

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3 years ago
One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe
sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                                 P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who disagree with the statement = \frac{1812}{2625} = 0.69

           n = sample of respondents = 2625

           p = population proportion of people who disagree with statement

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 99% confidence interval for the population proportion, p is ;</u>

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

                                                   of significance are -2.58 & 2.58}  

P(-2.58 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.58) = 0.99

P( -2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [ \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

= [ 0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } , 0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } ]

 = [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0
3 years ago
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