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bazaltina [42]
3 years ago
15

For a two-tailed test with a sample size of 20 and a .20 level of significance, the t value is _____. Selected Answer: d. 1.328

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

1.328

Step-by-step explanation:

Given :

Sample size, n = 20.

Degree of freedom, df = n - 1

df = 20 - 1 = 19

α = 0.2

Using the T-distribution calculator :

Since it is two - tailed:

Tα/2 ; 19 = T0.2/2 ; 19 = T0.1, 19 = 1.3277 = 1.328

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PLEASE PLEASE PLEASE HELP. :(
mart [117]
Integers are like -4,-3,-2,-1,0,1,2,3,4 etc

√49=7, integer

-3⁰=-(3⁰)=-(1)=-1, integer

1.2 times 10⁻²=1.2/100=0.012, not an integer

18/3=6, integer



answer is 3rd one
7 0
2 years ago
Yuet solved the equation 6 a minus 2 b = 12 for a. Her steps are shown below. 1. Subtract 2b: 6 a = 12 minus 12 b 2. Divide by 6
Ber [7]

Question:

Yuet solved the equation 6a - 2b = 12 for a.

Her steps are shown below.

1. Subtract 2b: 6a = 12 - 2b

2. Divide by 6: a = 2 - \frac{b}{3}

Answer:

In step 1 she needed to add 2b to both sides of the equation.

Step-by-step explanation:

Given:

The above steps shows how Yuet solved an equation

Required:

True statement about Yuet's work

The implication of the statement is to state what Yuet should have done instead of what she did.

In step 1, she subtracted 2b from both sides of the equation; this is wrong.

Instead of subtracting, she ought to add 2b to both sides of the equation.

The correct steps and result is as follows:

1. Add 2b: 6a = 12 + 2b

2. Divide by 6: a = 2 + \frac{b}{3}

Hence, we can conclude that in step 1 she needed to add 2b to both sides of the equation.

4 0
3 years ago
Read 2 more answers
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
0.00012 in scientific notation
Vladimir [108]

Answer:

1.2⋅10  

−4

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
GIVING BRAINLIEST WHOEVER ANSWER THIS CORRECT THANK U.
Sonja [21]

Answer:

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

Step-by-step explanation:

Translations

A given point A(x,y) when translated by the rule (h,k) maps to A'(x+h,y+k).

We are given the point X(3,-2) and its image at X'(2,-4). The rule for the translation used is:

(h,k)=(2,-4)-(3,-2)=(2-3,-4+2)=(-1,-2)

If we apply the same translation to the point Y(7,1) we get the image Y'(7-1,1-2)=Y'(6,-1).

If we apply the same translation to the point Z(-1,2) we get the image Z'(-1-1,2-2)=Z'(-2,0).

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

it's a example from another eqaqthion

6 0
2 years ago
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